Practicing Success
The integrating factor of the differential equation $\left(1-x^2\right) \frac{d y}{d x}-x y=1$, is |
$-x$ $\frac{x}{1+x^2}$ $\sqrt{1-x^2}$ $\frac{1}{2} \log \left(1-x^2\right)$ |
$\sqrt{1-x^2}$ |
We have, $\left(1-x^2\right) \frac{d y}{d x}-x y=1 \Rightarrow \frac{d y}{d x}-\left(\frac{x}{1-x^2}\right) y=\frac{1}{1-x^2}$ It is a linear differential equation with Integrating factor given by Integrating factor = $e^{-\int \frac{x}{1-x^2} d x}=e^{\frac{1}{2} \log \left(1-x^2\right)}=\sqrt{1-x^2}$ |