The integrating factor of the differential equation $\left(1-x^2\right) \frac{d y}{d x}-x y=1$, is
Answer & explanation
Correct answer: option 3
We have,
$\left(1-x^2\right) \frac{d y}{d x}-x y=1 \Rightarrow \frac{d y}{d x}-\left(\frac{x}{1-x^2}\right) y=\frac{1}{1-x^2}$
It is a linear differential equation with Integrating factor given by
Integrating factor = $e^{-\int \frac{x}{1-x^2} d x}=e^{\frac{1}{2} \log \left(1-x^2\right)}=\sqrt{1-x^2}$