Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solid State

Question:

Which of the following is the correct relationship between edge length (a) and radius of sphere (r) located in a fcc unit cell?

Options:

r = \(\frac{a}{2\sqrt{2}}\)

a = 2\(\sqrt{2}\)r

a = \(\frac{4r}{\sqrt{2}}\)

All of these

Correct Answer:

All of these

Explanation:

The correct answer is option 4. All of these.

Face centered cubic unit cell (FCC)

let the unit cell edge length be ‘a’ and face diagonal AC = b.

In ∆ ABC

AC2 = b2 = BC2 + AB2 = a2 + a2 = 2a2 or b = \(\sqrt{2}\)a

If r is the radius of the sphere, we find b = 4r = \(\sqrt{2}\)a or a = \(\frac{4r}{\sqrt{2}}\) 

a = 2\(\sqrt{2}\)r

we can also write, r = \(\frac{a}{2\sqrt{2}}\)