The instantaneous current from a a.c source is $I=10 \sin 314t$. The frequency of the source would be-
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) - 50 Hz
The equation of an AC is given as -
$I=I_0\sin (ωt)$
where,
$I_0$ = peak current
$ω$ = angular frequency
$t$ = time
$I=10\sin(314t)$ [given]
$∴ω=314\,rad/s$
$⇒f=\frac{ω}{2\pi}=\frac{314}{\pi}$
$f=\frac{314}{2×3.14}=50Hz$