Practicing Success
Practicing Success
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Two particles of masses m1 , m2 move with initial velocities u1 and u2 . On collision, one of the particles get excited to higher level, after absorbing energy \(\epsilon\). If final velocities of particles be v1 and v2 then we must have : |
\(\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2\) \(\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 - \epsilon = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2\) \(\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 + \epsilon = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2\) \(m_1u_1^2 + m_2u_2^2 = m_1v_1^2 + m_2v_2^2\) |
\(\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 - \epsilon = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2\) |
KEi - excitation energy = KEf ⇒ \(\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 - \epsilon = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2\) |
