The areas of similar triangles are 361 & 256 cm2. If the altitude of the smaller triangle is 8 cm, then the altitude of the bigger triangle in centimeter is?
Answer & explanation
Correct answer: option 2
Area = (side)2
\(\frac{361}{256}\) = (\(\frac{A_1}{A_2}\))2
\(\frac{19}{16}\) = \(\frac{A_1}{8}\)
⇒ A1 = 9.5 cm