The areas of similar triangles are 361 & 256 cm2.  If the altitude of the smaller triangle is 8 cm, then the altitude of the bigger triangle in centimeter is?

16 9.5 19 20

9.5

Area = (side)2 \(\frac{361}{256}\) = (\(\frac{A_1}{A_2}\))2 \(\frac{19}{16}\) = \(\frac{A_1}{8}\) ⇒ A1 = 9.5 cm