CUET Preparation Today
| If \(x\) is real, the minimum value of \(x^{2}-8x+17\) is |
\(-1\) \(0\) \(1\) \(2\) |
| \(1\) |
| \(\begin{aligned}f^{\prime}(x)&=2x-8\\ f^{\prime}(x)&=0\\ x&=4\\ f^{\prime \prime}&=2>0\end{aligned}\hspace{8cm}\) Minimum value \(=16-32+17=1\) |
