A charge of 20 µC lies at the centre of a square. Work done in carrying a charge of 5 µC from one corner of the square to the diagonally opposite corner is: |
50 J 100 J 0 J 4 J |
0 J |
The correct answer is Option (3) → 0 J Work Done, $W=qΔV$ where, q - test charge ΔV - potential difference between two points and, since the potential at both the starting and ending points is the same, the test charged is moved along the diagonal, and the potential at both corners are same due to symmetry. $ΔV=0$ $W=5μC×0=0$ |