If $(x^2+\frac{1}{x^2}) = 23, x > 0 $ What is the value of $(x^3+\frac{1}{x^3})$= ?
Answer & explanation
Correct answer: option 2
If $(x^2+\frac{1}{x^2}) = 23, x > 0 $
$(x^3+\frac{1}{x^3})$= ?
If $K^2+\frac{1}{K^2}$ = n
then, K+ \(\frac{1}{k}\) = \(\sqrt {n + 2}\)
x+ \(\frac{1}{x}\) = \(\sqrt {23 + 2}\) = 5
$(x^3+\frac{1}{x^3})$= 53 - 3 × 5 = 110