Evaluate the integral \(\int_0^Πsec^2x\,dx?\)
Answer & explanation
Correct answer: option 3
We have integral \(\int_0^Πsec^2x\,dx=?\)
⇒ \(\int_0^Πsec^2x\,dx=(tanx)\) for x = 0 to x= Π
= tan (Π) - tan (0)
= 0 - 0
= 0
Evaluate the integral \(\int_0^Πsec^2x\,dx?\)
Correct answer: option 3
We have integral \(\int_0^Πsec^2x\,dx=?\)
⇒ \(\int_0^Πsec^2x\,dx=(tanx)\) for x = 0 to x= Π
= tan (Π) - tan (0)
= 0 - 0
= 0