Practicing Success
The activation energy of a reaction is 9 kcal/mole. The increase in the rate constant when its temperature is raised from 295 to 300 is: |
14.9% 28.9% 78.9% 82.9% |
28.9% |
To determine the increase in the rate constant when the temperature is raised, we can use the Arrhenius equation: \[ k = A \cdot e^{-\frac{E_a}{RT}} \] Where: To calculate the increase in the rate constant, we can compare the rate constants at two different temperatures. Let's consider the temperatures 295 K and 300 K. \[ \frac{k_2}{k_1} = \frac{A \cdot e^{-\frac{E_a}{RT_2}}}{A \cdot e^{-\frac{E_a}{RT_1}}} = e^{\frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)} \] Substituting the given values: Calculating the ratio: To find the increase in the rate constant, we subtract 1 from the ratio and multiply by 100%: Increase in rate constant = (1.289 - 1) × 100% ≈ 28.9% Therefore, the correct answer is (2) 28.9%. |