A voltage V = 5 Cos \(15\pi \)t V flows through a resistor of 33 \(\Omega \). What will be the average value of current flowing through the circuit?
Answer & explanation
Correct answer: option 1
I = \(\frac{V}{R}\) = 0.2 Cos \(15\pi \)t A
Iavg = 0.636Io = 0.636 x 0.2 = 0.13 A