Practicing Success
A mass M is lowered with the help of a string by a distance h at a constant acceleration g/2. The work done by the string will be : |
\(\frac{-Mgh}{2}\) \(\frac{-3Mgh}{2}\) \(\frac{Mgh}{2}\) \(\frac{3Mgh}{2}\) |
\(\frac{-Mgh}{2}\) |
Tension in the string : \(T = M(g - a) = M(g - \frac{g}{2})\) \(T = Mg\) W = force x displacement = \(-\frac{Mgh}{2}\) Negative sign is because tension is in the upward direction and displacement is in the downward direction. |