The total energy of the electron in a hydrogen atom is -1.51eV A. Its Kinetic energy is -1.51eV Choose the correct answer from the options given below: |
C and D only B and D only A, B and C only B and C only |
B and C only |
The correct answer is Option (4) → B and C only (B) Since the total energy E is $-1.51eV$ and the $KE=-\frac{U}{2}$, $E=K+U=-\frac{U}{2}+U=\frac{U}{2}$ $⇒U=2E=-3.02eV$ (C) The total energy for a hydrogen atom is - $E=-\frac{13.6}{n^2}eV$ $⇒n^2=\frac{13.6}{1.51}≃9⇒n=3$ Hence, the electron is in second excited state. |