Practicing Success
Practicing Success
CUET Preparation Today
The current in a coil falls from 5.0 A to 0.0 A in 0.1 s. If average emf of 200 V is induced, the value of self inductance of coil is: |
2 H 4 H 3 H 1 H |
4 H |
$ |\xi| = L \frac{\Delta I}{\Delta t}$ $ L = \xi \frac{\Delta t}{\Delta I} = 200\times \frac{0.1}{5} = 4H$ |
