Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Linear Programming

Question:

$y=x(x-3)^2$ decreases for the value of x given by

Options:

$0<x<\frac{3}{2}$

x > 0

1 < x < 3

x < 0

Correct Answer:

1 < x < 3

Explanation:

The correct answer is Option (3) - 1 < x < 3