The area (sq.units) bounded by the curve $y = \sin x,π ≤ x ≤ 2π$ and the x-axis is

2

The correct answer is Option (2) → 2

Given: $y = \sin x$, interval: $x \in [\pi, 2\pi]$

On $[\pi, 2\pi]$, $\sin x \leq 0$

Required area = $\int_{\pi}^{2\pi} | \sin x | \, dx = - \int_{\pi}^{2\pi} \sin x \, dx$

$= - [ -\cos x ]_{\pi}^{2\pi} = \cos \pi - \cos(2\pi)$

$= (-1) - (1) = -2$

Area = ${2}$ sq. units