Practicing Success
Practicing Success
CUET Preparation Today
If $f(x)=\left\{\begin{matrix}ax^2+b, & x<-1\\bx^2+ax+4, & x≥-1\end{matrix}\right.$ is everywhere differentiable, then : |
$a=2, b=3$ $a=3, b=2$ $a=-2, b=3 $ $a=2, b=-3$ |
$a=2, b=3$ |
