If sin x = 3/5, 0 ≤ x ≤ 90°, then the value of cot x. sec x is :

Given :-

sinx = \(\frac{3 }{5}\)

{ sinx = \(\frac{P }{H}\) }

P² + B² = H²

3² + B² = 5²

9 + B² = 25

B = 4

Now,

cotx . secx

= \(\frac{4 }{3}\) × \(\frac{5}{4}\) 

= \(\frac{5}{3}\)