Practicing Success
Practicing Success
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If $sin x = \frac{3}{5}$, 0 ≤ x ≤ 90°, then the value of $cot x. sec x$ is : |
$\frac{3}{5}$ $\frac{5}{3}$ $\frac{4}{5}$ $\frac{3}{4}$ |
$\frac{5}{3}$ |
Given :- sinx = \(\frac{3 }{5}\) { sinx = \(\frac{P }{H}\) } P² + B² = H² 3² + B² = 5² 9 + B² = 25 B = 4 Now, cotx . secx = \(\frac{4 }{3}\) × \(\frac{5}{4}\) = \(\frac{5}{3}\) |
