If \(\int e^{x}[f(x)+f^{\prime}(x)]dx=e^{x}\sin x+c\) then \(f(x)\) is equal to

\(\cos x\) \(\sin x\) \(e^{x}\cos x\) \(e^{x}\sin x\)

\(\sin x\)

Since \(\int e^{x}[f(x)+f^{\prime}(x)]dx=e^{x}f(x)+c\) So, \(f(x)=\sin x\)