Match List I with List II
| LIST I | LIST II |
| A. Buna-S | I. Polyamide |
| B. Nylon 6, 6 | II. Homopolymer |
| C. Polythene | III. Terephthalic acid, ethylene glycol |
| D. Terylene | IV. Copolymer |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is option 3. A-IV, B-I, C-II, D-III.
| LIST I | LIST II |
| A. Buna-S | IV. Copolymer |
| B. Nylon 6, 6 | I. Polyamide |
| C. Polythene | II. Homopolymer |
| D. Terylene | III. Terephthalic acid, ethylene glycol |
Let us go through the matching in detail:
List I:
A. Buna-S - This is a synthetic rubber, which is generally a copolymer of butadiene and styrene. It is a copolymer because it contains two different monomers.
B. Nylon 6, 6 - This is a polyamide, specifically formed from adipic acid and hexamethylene diamine. It is a type of polymer where the monomers contain amide functional groups.
C. Polythene - This is polyethylene, which is a homopolymer. It is made up of repeating units of only one type of monomer, in this case, ethylene.
D. Terylene - This is a polyester, made from terephthalic acid and ethylene glycol. It is a type of polymer where the monomers are ester functional groups.
List II:
I. Polyamide - Matches with Nylon 6, 6 (B), which is formed from two different monomers that include an amide functional group.
II. Homopolymer - Matches with Polythene (C), which is a polymer made from a single type of monomer, ethylene in this case.
III. Terephthalic acid, ethylene glycol - Matches with Terylene (D), a polyester formed from these two monomers.
IV. Copolymer - Matches with Buna-S (A), a synthetic rubber that is a copolymer of butadiene and styrene.
So, the correct matching is 3. A-IV, B-I, C-II, D-III. I appreciate your patience, and I hope this clarifies the explanation.