What is the average of the cubes of the first 7 natural numbers?

Formula used :-

Sum of cubes of first n natural numbers = \(\frac{n(n+1)(n+1)}{2}\)

Now , Sum of cubes of first 7 natural numbers = \(\frac{7(7+1)(7+1)}{2}\)

= 784

Average = \(\frac{784}{7}\) = 112