If two numbers 121 and 199 are divided by two digits number then leaves the same remainder in each case. How many two digits numbers of such type are possible?
Answer & explanation
Correct answer: option 1
Required number = HCF and factors of HCF of (121 - x), (199 - x)
121 199
↓ ↓
Diff. = 78 (HCF)
Required numbers = 78 and two digit factors of 78
= 78, 39, 26, 13
∴ 4 numbers are possible