Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

The maximum power drawn out of cell is given by : (E is emf, r is internal resistance)

Options:

$\frac{E^2}{2r}$

$\frac{E^2}{4r}$

$\frac{E^2}{r}$

$\frac{E^2}{3r}$

Correct Answer:

$\frac{E^2}{4r}$

Explanation:

The correct answer is Option (2) → $\frac{E^2}{4r}$