CUET Preparation Today
CUET
Physics
Current Electricity
The maximum power drawn out of cell is given by : (E is emf, r is internal resistance)
$\frac{E^2}{2r}$
$\frac{E^2}{4r}$
$\frac{E^2}{r}$
$\frac{E^2}{3r}$
The correct answer is Option (2) → $\frac{E^2}{4r}$
