If three unbiased coins are tossed simultaneously, then the probability of exactly two heads is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{3}{8}$
When three unbiased coins are tossed, the total number of possible outcomes is:
$2^3 = 8$
Step 1: Outcomes with exactly two heads
The favorable outcomes are:
- HHT
- HTH
- THH
So, number of favorable outcomes = 3
Step 2: Probability
$\text{Probability} = \frac{3}{8}$