If three unbiased coins are tossed simultaneously, then the probability of exactly two heads is:

$\frac{3}{8}$

The correct answer is Option (1) → $\frac{3}{8}$

When three unbiased coins are tossed, the total number of possible outcomes is:

$2^3 = 8$

Step 1: Outcomes with exactly two heads

The favorable outcomes are:

• HHT
• HTH
• THH

So, number of favorable outcomes = 3

Step 2: Probability

$\text{Probability} = \frac{3}{8}$