AB is a chord in the minor segment of a circle with center O. C is a point on the minor arc (between A and B). The tangents to the circle at A and B meet at a point P. If ∠ACB = 104°, then ∠APB is equal to ? |
28° 36° 40° 54° |
28° |
Here note the direct result: ∠APB = 2 ∠ACB - 180° Hence, ∠APB = 2 (104°)- 180° = 208° - 180° = 28° |