The feasible region associated with the inequality 2x + 3y > 4 is

The correct answer is Option (2) → Open half plane not containing the origin

Given inequality $2x+3y>4$

Boundary line is $2x+3y=4$.

Since the inequality is strict, the boundary line is not included, so the region is an open half plane.

Check whether origin lies in the region.

At $(0,0)$, $2(0)+3(0)=0$

$0>4$ is false.

So origin does not lie in the feasible region.

Open half plane not containing the origin