The length of the longest diagonal that can be placed in a closed cube is $50\sqrt{3}$ cm. What is the total surface area of this cube?
Answer & explanation
Correct answer: option 1
We know that,
Diagonal of cube = \(\sqrt {3}\) × Side of cube
The total surface area of cube = 6(side)²
We have,
Diagonal = 50\(\sqrt {3}\) cm.
According to the question,
side\(\sqrt {3}\) = 50\(\sqrt {3}\)
side = 50
Now, Total surface area of cube = 6 ×(50)² = 15000cm²