CUET Preparation Today
\(\int\limits_0^\pi \sin ^3 x \cdot \cos ^2 x \cdot d x = \) |
\(\frac{-4}{15}\) \(\frac{2}{15}\) 0 \(\frac{4}{15}\) |
\(\frac{4}{15}\) |
\(I=2\int\limits_0^{\pi/2} \sin ^3 x × \cos ^2 x dx \) By applying $\int\limits_a^b+(x)dx=\int\limits_a^bf(a+b-x)dx....$ $=\frac{2×(3-1)(3-2)(2-1)}{5×3×1}=\frac{4}{15}$ Option 4 is correct. |
