Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Definite Integration

Question:

\(\int\limits_0^\pi \sin ^3 x \cdot \cos ^2 x \cdot d x = \)

Options:

\(\frac{-4}{15}\)

\(\frac{2}{15}\)

0

\(\frac{4}{15}\)

Correct Answer:

\(\frac{4}{15}\)

Explanation:

\(I=2\int\limits_0^{\pi/2} \sin ^3 x × \cos ^2 x dx \)

By applying $\int\limits_a^b+(x)dx=\int\limits_a^bf(a+b-x)dx....$

$=\frac{2×(3-1)(3-2)(2-1)}{5×3×1}=\frac{4}{15}$

Option 4 is correct.