CUET Preparation Today
The area bounded by the curve $y=sin\, x$ between x=0 and $x= 2\pi $ is : |
4 sq.units $4\pi $ sq.units 0 2 sq.units |
4 sq.units |
by symmetry area from $0 → \frac{π}{2}$ = area from $\frac{π}{2}→π$ = area from $π→\frac{3π}{2}$ = area from $\frac{3π}{2}→2π$ so area = 4 area from $0 → \frac{π}{2}$ $=4\int\limits_{0}^{π/2}\sin xdx$ $=4[-\cos x]_{0}^{π/2}$ = 4 sq. units |
