The function \(\frac{\log x}{x}\) attains its maximum at the point
Answer & explanation
Correct answer: option 1
\(\begin{aligned}f^{\prime}(x)&=\frac{1-\log x}{x^{2}}\\ \text{So }f^{\prime}(x)&=0\Rightarrow x=e\\ f^{\prime \prime}(e)&<0\end{aligned}\)