CUET Preparation Today
| The function \(\frac{\log x}{x}\) attains its maximum at the point |
\(x=e\) \(x=\frac{1}{e}\) \(x=\sqrt{e}\) None of these |
| \(x=e\) |
| \(\begin{aligned}f^{\prime}(x)&=\frac{1-\log x}{x^{2}}\\ \text{So }f^{\prime}(x)&=0\Rightarrow x=e\\ f^{\prime \prime}(e)&<0\end{aligned}\) |
