X and Y starts at same time from A to B . After reaching at B they turned to their starting point and they meet at 10 km apart from B . If the speed of X is 16 km less than Y and the distance between A and B are 45 km apart then find the speed of Y .
Answer & explanation
Correct answer: option 3
X travels 16 km/hr slower than Y
Let speed of X = A km/hr
Speed of Y =( A + 16 ) km/hr
Y reaches place B and turns back to meet X , 10 km from place B
So distance traveled by Y = 45 + 10 = 55 km
Distance traveled by X = 45 - 10 = 35 km
According to question ,
\(\frac{55}{A \; + \;16}\) = \(\frac{35}{A}\)
55A = 35A + 560
20A = 560 ⇒ A = 28
Speed of Y =( A + 16 ) km/hr = ( 28 + 16 ) = 44 km/hr