X and Y starts at same time from A to B . After reaching at B they turned to their starting point and they meet at 10 km apart from B . If the speed of X is 16 km less than Y and the distance between A and B are 45 km apart then find the speed of Y .

44 km/hr

X travels 16 km/hr slower than Y 

Let speed of X = A km/hr 

Speed of Y =( A + 16 ) km/hr

Y  reaches place B and turns back to meet X , 10 km from place B

So distance traveled by Y = 45 + 10 = 55 km 

Distance traveled by X = 45 - 10 = 35 km

According to question , 

\(\frac{55}{A \; + \;16}\)  =  \(\frac{35}{A}\)

55A = 35A + 560

20A = 560   ⇒   A = 28

Speed of Y =( A + 16 ) km/hr = ( 28 + 16 ) = 44 km/hr