The compound interest on ₹4,000 at the rate of 5% p.a. is ₹630.50, then the time period is: |
2 years $3\frac{1}{2}$ years 3 years $1\frac{1}{2}$ years |
3 years |
The formula that we used here is :- Compound interest = Amount - Principal Compound interest = P$(1 \;+\; \frac{R}{100})^t$ - P 630.50 = 4000 [$(1 \;+\; \frac{5}{100})^t$- 1 ] \(\frac{1261}{8000}\) = [ $(1 \;+\; \frac{1}{20})^t$ - 1 ] \(\frac{1261}{8000}\) + 1 = ( 1 + \(\frac{1}{20}\) )t \(\frac{9261}{8000}\) = ( \(\frac{21}{100}\) )t ( \(\frac{21}{20}\) )³ =( \(\frac{21}{20}\) )t So, t = 3 Hence , time is 3 years. |