Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

Form the differential equation of the family of curve represented by $x^2 + y^2 = 2ax$, $a$ being the parameter.

Options:

$x^2-y^2=2xy\frac{dy}{dx}$

$2xy\frac{dy}{dx}=y^2-x^2$

$2xy\frac{dy}{dx}+x^2+y^2$

$x^2+y^2=2a$

Correct Answer:

$2xy\frac{dy}{dx}=y^2-x^2$

Explanation:

The correct answer is Option (2) → $2xy\frac{dy}{dx}=y^2-x^2$

Given $x^2 + y^2 = 2ax$, $a$ being the parameter   ...(1)

Differentiating it w.r.t. x, we get

$2x + 2y\frac{dy}{dx}= 2a$.

Putting this value of $2a$ in (1), we get $x^2 + y^2 = \left(2x+2y\frac{dy}{dx}\right)x$

$⇒ 2xy\frac{dy}{dx}= y^2 - x^2$, which is the required differential equation of the given family of curve.