Form the differential equation of the family of curve represented by $x^2 + y^2 = 2ax$, $a$ being the parameter. |
$x^2-y^2=2xy\frac{dy}{dx}$ $2xy\frac{dy}{dx}=y^2-x^2$ $2xy\frac{dy}{dx}+x^2+y^2$ $x^2+y^2=2a$ |
$2xy\frac{dy}{dx}=y^2-x^2$ |
The correct answer is Option (2) → $2xy\frac{dy}{dx}=y^2-x^2$ Given $x^2 + y^2 = 2ax$, $a$ being the parameter ...(1) Differentiating it w.r.t. x, we get $2x + 2y\frac{dy}{dx}= 2a$. Putting this value of $2a$ in (1), we get $x^2 + y^2 = \left(2x+2y\frac{dy}{dx}\right)x$ $⇒ 2xy\frac{dy}{dx}= y^2 - x^2$, which is the required differential equation of the given family of curve. |