Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Indefinite Integration

Question:

\(\int \frac{\sin^{2} x}{\cos^{6}x} dx\) is

Options:

A polynomial of degree \(5\) in \(\sin x\)

A polynomial of degree \(4\) in \(e^x\)

A polynomial of degree \(5\) in \(\cos x\)

A polynomial of degree \(5\) in \(\tan x\)

Correct Answer:

A polynomial of degree \(5\) in \(\tan x\)

Explanation:

\(\begin{aligned}\int \frac{\sin^{2} x}{\cos^{6}x} dx&=\int \tan^{2} x \sec^{2} x\sec^{2} x dx\\ &=\int \tan^{2} x (1+\tan^{2} x)\sec^{2} x dx\\ &=\int t^{2}(1+t^{2})dt, \text{ where }\tan x=t, \sec^{2} x dx=dt\\ &=\frac{t^{5}}{5}+\frac{t^{3}}{3}+c\\ &=\frac{\tan^{5} x}{5}+\frac{\tan^{3}x}{3}+c\end{aligned}\)