Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Definite Integration

Question:

\(\int_{0}^{\frac{\pi}{2}}\frac{\sqrt{\sin x}}{\sqrt{\sin x}+\sqrt{\cos x}}dx=\)

Options:

\(\frac{\pi}{2}\)

1

\(\pi\)

\(\frac{\pi}{4}\)

Correct Answer:

\(\frac{\pi}{4}\)

Explanation:

Use the property \(\int_{a}^{b}f(x)dx=\int_{a}^{b}f(a+b-x)dx\)