If $xe^y = 1$, then the value of $\frac{dy}{dx}$ at $x = 1$ is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $-1$ ##
We have $xe^y = 1$.
Differentiating w.r.t. '$x$' both sides:
$1 \cdot e^y + xe^y \frac{dy}{dx} = 0$
$xe^y \frac{dy}{dx} = -e^y$
$\frac{dy}{dx} = -\frac{1}{x}$
$∴\left. \frac{dy}{dx} \right|_{x=1} = -1$