In the right triangle shown in the figure ,what is the value of cosec $\theta$ ?
Answer & explanation
Correct answer: option 1
By using pythagoras theorem ,
P² + B² = H²
ATQ,
B = 5 and H = 13
P² + 5² = 13²
P² = 169 - 25
P² = 144
P = 12
cosecθ = \(\frac{H}{P}\)
= \(\frac{13}{5}\)