Which of the following matrix is not skew symmetric matrix? |
$\left[\begin{array}{cc}0 & 1 \\ -1 & 0\end{array}\right]$ $\left[\begin{array}{cc}0 & -3 \\ 3 & 1\end{array}\right]$ $\left[\begin{array}{cc}0 & -2 \\ 2 & 0\end{array}\right]$ $\left[\begin{array}{ccc}0 & 1 & -2 \\ -1 & 0 & -3 \\ 2 & 3 & 0\end{array}\right]$ |
$\left[\begin{array}{cc}0 & -3 \\ 3 & 1\end{array}\right]$ |
a skew matrix is one which follows following property symmetric A = -AT Transpose of a matrix A Let A = [aij]m×n → A is a matrix of order m×n aij → represents its ith, jth element AT = [aji]n×m for skew symmetric matrix A = -AT → every aij = -aji so for diagonal elements aii = -aii → both indices are represented by i, i since its a diagonal element ⇒ 2aii = 0 ⇒ aii = 0 → for skew symmetric matrices its diagonal entries are always zero → necessary condition for skew symmetric matrices So we need to check only these matrices whose diagonal entries are not zero first In this case we will check for option 2 $A=\left[\begin{array}{cc}0 & -3 \\ 3 & 1\end{array}\right]$ → non zero diagonal entries $A^T=\left[\begin{array}{cc}0 & 3 \\ -3 & 1\end{array}\right]$ $-A^T=\left[\begin{array}{cc}0 & -3 \\ 3 & -1\end{array}\right]$ ⇒ A ≠ - AT option 2 → not skew symmetric matrix |