Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Moving Charges and Magnetism

Question:

Which of the following is true about the motion of a charged particle in a perpendicular magnetic field?

Options:

The work done by the field is qvB Sin θ.

There is finite amount of work done in moving the charged particle from one point to another.

There may or may not be change in the momentum of the particle.

There may or may not be change in the velocity of the particle.

Correct Answer:

There may or may not be change in the momentum of the particle.

Explanation:

The work done by the field is zero.

There is zero amount of work done in moving the charged particle from one point to another as the field is perpendicular to the motion of the particle.

There will not be any change in the velocity of the particle as the work done by force is zero.