Directions : In each of the following questions, find the odd letter/number pair from the given alternatives.

RJ16

The logic is:

last number is double the number of alphabet between first and second letter in the English alphabet

= ZS12 → (difference between Z and S is 7)

  7 × 2 = 14 ≠ 12

= RJ16 → (difference between R and J is 8)

  8 × 2 = 16 = 16

= YQ14 → (difference between Y and Q is 8)

  8 × 2 = 16 ≠ 14

= FD12 → (difference between F and D is 2)

  2 × 2 = 4 ≠ 12