The area of a circular path enclosed by two concentric circles is 3080 m2. If the difference between the radius of the outer edge and that of inner edge of the circular path is 10 m, what is the sum (in m) of the two radii? (Take $π = \frac{22}{7}$) |
112 70 84 98 |
98 |
We know that, Area of circle = πr2 We have, The area of a circular path enclosed by two concentric circles = 3080 m2 The difference between the radius of the outer edge and that of inner edge of the circular path = 10 m Let, The outer edge of the radius of the circle = R The inner edge of the radius of the circle = r According to the question = (R – r) = 10 m .....(A) Area of circle = π(R2 – r2) = 3080 = \(\frac{22}{7}\) × (R + r)(R – r) = 3080 = (R + r)(R – r) = 980 = (R + r)(10) = 980 = (R + r) = ( \(\frac{980}{10}\) ) = 98 m |