The area of a circular path enclosed by two concentric circles is 3080 m². If the difference between the radius of the outer edge and that of inner edge of the circular path is 10 m, what is the sum (in m) of the two radii? (Take $π = \frac{22}{7}$)

98

We know that,

Area of circle = πr²

We have,

The area of a circular path enclosed by two concentric circles = 3080 m²

The difference between the radius of the outer edge and that of inner edge of the circular path = 10 m

Let, The outer edge of the radius of the circle = R

The inner edge of the radius of the circle = r

According to the question

= (R – r) = 10 m .....(A)

Area of circle = π(R² – r²) = 3080

= \(\frac{22}{7}\) × (R + r)(R – r) = 3080

= (R + r)(R – r) = 980

= (R + r)(10) = 980

= (R + r) = ( \(\frac{980}{10}\) ) = 98 m