Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

Select a graph for concave mirror between 1/v and 1/u.

Options:

Correct Answer:

Explanation:

For a mirror

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$

let $y = \frac{1}{v}, x = \frac{1}{u}$

$∴ x + y = \frac{1}{f}, y = – x + 1/f$

This is the equation of a straight line with slope = (–1) and intercept =$\frac{1}{f}$

Hence the graph would be