The side of a rhombus is 25 m, and one of its diagonal is 30 meters. What is its area?

600 sq m

Applying Pythagoras theorem: (25)² - ( \(\frac{ 30}{ 2}\) )² =  (half of 2nd diagonal)²

625 - (15)² = (half of 2nd diagonal)²

625 - 225 = (half of 2nd diagonal)²

400 = (half of 2nd diagonal)²

20 = half of diagonal

Thus, we can say that length of the diagonal is 40 m

Area of a rhombus = \(\frac{ 1}{ 2}\) x D₁ x D₂

Area = \(\frac{ 1}{ 2}\) x 30 x 40

Area = 600 sq m