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A galvanometer coil has a resistance of 15 Ω and the metre shows full scale deflection for a current of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A |
Shunt resistance = 10 mΩ Resistance in series = 5988 Ω 1.4 A,C A, 11.9 |
Shunt resistance = 10 mΩ |
$ R_G = 15\Omega$
$\text{Current for which galvanometer shows full scale deflection is i = 4mA.}$
$\text{Range of ammeter is 4 mA, we have to convert this range to 6mA.}$
$\Rightarrow I = 6mA$
$\text{ we need to add a small resistance $R_P$ in parallel to the galvanometer}$
$R_P = \frac{i R_G}{I -i} = 10m\Omega$
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