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Find the value of x if \(\begin{vmatrix}3x^2 & 1 \\10 & x \end{vmatrix}\) = \(\begin{vmatrix}4 & 3 \\3 & 20 \end{vmatrix}\) |
-3 3 Both (a) and (b) Cannot be determined |
3 |
On solving the determinants we get \(3 { x }^{ 3 } -10=71\) \(3 { x }^{ 3 } =81\) \({ x }^{ 3 } =27\) x=3 |
