CUET Preparation Today
What is the value of \(\frac{(0.7)^3 + (0.3)^3}{(0.7)^2 - 0.7 × 0.3 + (0.3)^2}\)
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0.4 0.7 1.0 0 |
1.0 |
\(\frac{a^3 + b^3}{a^2 + b^2 - ab}\) → \(\frac{(a + b) (a^2 + b^2 -ab)}{(a^2 + b^2 - ab)}\) = a + b a = 0.7, b = 0.3 So, 0.7 + 0.3 = 1 |
