Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

What is the value of \(\frac{(0.7)^3 + (0.3)^3}{(0.7)^2 - 0.7 × 0.3 + (0.3)^2}\)

 

 

Options:

0.4

0.7

1.0

0

Correct Answer:

1.0

Explanation:

\(\frac{a^3 + b^3}{a^2 + b^2 - ab}\) → \(\frac{(a + b) (a^2 + b^2 -ab)}{(a^2 + b^2 - ab)}\) = a + b

a = 0.7, b = 0.3

So, 0.7 + 0.3 = 1