CUET Preparation Today
A radioactive isotope has a half life of T years. How long (in years) will it take the activity to reduce to 3.125% of it's original value ? |
4T 5T 3T 6T |
5T |
$ N = \frac{N_0}{2^{\frac{t}{T}}}= \frac{N_0}{32} = \frac{N_0}{2^5}$ $ \frac{t}{T} = 5 \Rightarrow t = 5T$ |
