Evaluate the integral \(\int_0

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Definite Integration

Question:

Evaluate the integral \(\int_0^Πsin2x\,dx=?\)

Options:

-1/2

-1

1/2

Correct Answer:

Explanation:

We have integral \(\int_0^Πsin2x\,dx=?\)

⇒ \(\int_0^Πsin2x\,dx=-1/2(cos2x)\) for x = 0 to x= Π

= -1/2(cos2Π - cos0 )

= -1/2(1-1)

= 0