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CUET
-- Mathematics - Section B1
Definite Integration
Evaluate the integral \(\int_0^Πsin2x\,dx=?\)
0
-1/2
-1
1/2
We have integral \(\int_0^Πsin2x\,dx=?\)
⇒ \(\int_0^Πsin2x\,dx=-1/2(cos2x)\) for x = 0 to x= Π
= -1/2(cos2Π - cos0 )
= -1/2(1-1)
= 0
