Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

What is the minimum value of  y = \(\frac{ { x }^{ 2 } }{2}-3x\)?

Options:

\[{9/2}\]

\[{-9/2}\]

\[{9/4}\]

\[{-9/4}\]

Correct Answer:

\[{-9/2}\]

Explanation:

minimum value occurs at x= 3