${_{70}Yb^{2+}}$ and ${_{71}Lu^{3+}}$ Lanthanoid ions. .............
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → Diamagnetic and diamagnetic respectively
Let's analyze the electronic configurations of the given lanthanoid ions:
1. 70Yb²⁺ (Ytterbium(II))
- Atomic number of Yb = 70 → neutral Yb: [Xe] 4f¹⁴ 6s²
- Yb²⁺ → loses 2 electrons → [Xe] 4f¹⁴
- 4f¹⁴ → fully filled → diamagnetic
2. 71Lu³⁺ (Lutetium(III))
- Atomic number of Lu = 71 → neutral Lu: [Xe] 4f¹⁴ 5d¹ 6s²
- Lu³⁺ → loses 3 electrons → [Xe] 4f¹⁴
- 4f¹⁴ → fully filled → diamagnetic
Both ions are diamagnetic